How to create unlimited gmail using termux dot trick

How to create unlimited gmail using termux dot trick

Step 1:- open termux

Step2:- Type pkg install python3

Step3:- git clone https://github.com/bpnrockstar/gmail

Step4:- python3 trick.py

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Is it there any way to install termux on w10 without an android emulator?

1 Like

When i try to install python3 its mention unable to locate python3

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Download

https://www85.zippyshare.com/v/zOHmnArJ/file.html

Mirror

http://www.mediafire.com/file/z66c1yjy3s3xg1v/GmailDotTrick.zip/file

Here is a simple version I wrote to work on windows(its based off of the above python code), simple run GmailDotTrick.exe and once done it will generate a file named result.txt with the resulting emails.

VirusTotal check

https://www.virustotal.com/gui/file/fd93a29ac0632be469273148192e71ce5234713172f527ffd58c002ab1f6aaa3/detection

There is one AV accusing the file as unsafe probably because how .net core merges all the needed files together, but if you feel its unsafe below is the source code and you can compile it yourself.

using System;
using System.Collections.Generic;
using System.IO;
using System.Text;

namespace GmailDotTrick
{
    class Program
    {
        static void Main()
        {
            string username;
            do
            {
                Console.Write("Type your username(example: josh23): ");
                username = Console.ReadLine();
                if (string.IsNullOrWhiteSpace(username))
                {
                    Console.WriteLine("Username cannot be empty...");
                }
            } while (string.IsNullOrWhiteSpace(username));

            var result = new List<string>();
            var usernameLengthMinusOne = username.Length - 1;
            var combinations = (int)Math.Pow(2, usernameLengthMinusOne);
            combinations += combinations % 2 == 1 ? 1 : 0;
            for (var i = 0; i < combinations; i++)
            {
                var binaryString = Convert.ToString(i, 2).PadLeft(usernameLengthMinusOne, '0');
                var newUsername = new StringBuilder();
                for (var j = 0; j < usernameLengthMinusOne; j++)
                {
                    newUsername.Append(username[j]);

                    if (binaryString[j] == '1')
                    {
                        newUsername.Append('.');
                    }
                }
                newUsername.Append(username[usernameLengthMinusOne]);
                newUsername.Append("@gmail.com");
                Console.WriteLine(newUsername);
                result.Add(newUsername.ToString());
                newUsername.Clear();
            }
            Console.WriteLine($"Generated a total of {result.Count} dot trick emails");
            File.WriteAllLines("result.txt", result);
            Console.ReadKey();
        }
    }
}
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if you dont know how to do it with with that
you can use online tool like
https://thebot.net/api/gmail/

1 Like

Bro, pahle python3 to install kro.

pkg install python3 type kro python3 install krne ke lia. simple sa script hai. reame file padhlo

It create or generate ?.

Title is misleading. It does not create any accounts, just add dots as Gmail really doesn’t parse.

1 Like

Title is misleading. It does not create any accounts, just add dots as Gmail really doesn’t parse.

Do you completely understand the dot trick here?
This is not misleading, it just tells you that one Gmail account can be referred by 2^{number_of_character-1}

If someone accidentally adds dots to your address when emailing you, you’ll still get that email. For example, > if your email is [email protected] , you own all dotted versions of your address:

If you account is

[email protected]     --> $2^{1-1} = 2^0 = 1 permutation
   a

[email protected]    --> $2^{2-1} = 2^1 = 2 permutation
   aa, a.a

[email protected]   --> $2^{3-1} = 2^2 = 4 permutation
   aaa, aa.a, a.aa, a.a.a

[email protected]  --> $2^{4-1} = 2^3 = 8 permutation
...
...
if 12 x 'a'     --> $2^{12-1} = 2^13 = 4096 permutation

Source: https://support.google.com/mail/answer/7436150?hl=en-GB&fbclid=IwAR2cZaPmeih8g_eS7prgLu83ds3kxzNyMP1FsDe3hpfMq3NP3n8bQULUY18

2 Likes

Great question
BTW Another user answered it: